Question

from quadratic polynomial sum and product of whose zeros are 1 and -12 respectively

Answer 1

sum of zeroes ==》 1
product of zeroes ==》 -12
Formula for quardatic equation:-

x^2 + (sum)x - (product) =0
Now, put the value of sum and product in formula..

x^2 + x -(-12)=0
x^2 + x +12 =0.....

HOPE u understand##...
Thanks☺

Answer 2

Answer:

$\text{The polynomial is }x^2-x-12=0$

Step-by-step explanation:

Given the sum and product of zeroes which are 1 and -12 respectively.

we have to form the quadratic polynomial.

The quadratic polynomial is of the form

$x^2-(\text{Sum of zeroes})x+(\text{Product of zeroes})=0$

Sum of zeroes=1

Product of zeroes=-12

Hence, the polynomial is

$x^2-x-12=0$

which is required polynomial.