Plz solve...Q. 5 ....... i need it's solution..
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Here is your answer ,,,,
construction = let us join B to D .
proof = According to mid pt theorem..
so Sp parallel to BD and sp= 1÷2 of BD ---------equation 1
similarly, ,,,
QR parallel to BD . AND QR = 1÷2 OF BD -------equation 2
now from 1 and 2 we get .
sp parallel to QR
AND SP = QR .
now quadrilateral having one of its opposite side parallel and equal ..
theirfore ,,, PQRS is the required rectangle. .
plz mark my Answer as brainliest....--------
construction = let us join B to D .
proof = According to mid pt theorem..
so Sp parallel to BD and sp= 1÷2 of BD ---------equation 1
similarly, ,,,
QR parallel to BD . AND QR = 1÷2 OF BD -------equation 2
now from 1 and 2 we get .
sp parallel to QR
AND SP = QR .
now quadrilateral having one of its opposite side parallel and equal ..
theirfore ,,, PQRS is the required rectangle. .
plz mark my Answer as brainliest....--------
Anonymous:
U had to prove parallelogram PQRS not ABCD.
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