Question

plz solve the question​

Answer 1

Answer:

Given:

Equation of 2 SHM are :

$1) \: y1 = a \sin( \omega t + \phi) \\ 2) \: y2 = a \sin( \omega t)$

To find:

Phase difference between the two SHMs.

Concept:

SHM is a type of oscillatory motion in which the ones follows a specified rule of :

$\boxed{ \red{F = - ky}}$

In this type of Motion, phase denotes the the position of the object with respect to

time.

Phase is denoted by radian angle.

Calculation:

Phase of 1st SHM is :

$phase1 = \omega t + \phi$

Phase of 2nd SHM is:

$phase2 = \omega t$

So phase difference

$\boxed{ \red{ \bold{ \Delta phase = \phi}}}$

Answer 2

Answer:

Equation of 2 SHM are :

Explanation:

1)y1=asin(ωt+ϕ)

2) y2=asin(wt)

To find:

Phase difference between the two SHMs.

Concept:

SHM is a type of oscillatory motion in which the ones follows a specified rule of :

$\large\pink{\boxed{ \red{F = - ky}}}$

In this type of Motion, phase denotes the the position of the object with respect to

time.

Phase is denoted by radian angle.

Calculation:

Phase of 1st SHM is :

phase1 =ωt+ϕ

Phase of 2nd SHM is:

phase2 =ωt

So phase difference

$\boxed{ \red{ \bold{ \Delta phase = \phi}}}$