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Q is a point on the side SR of triangle PSR such that PQ=PR. Prove that PS>PQ.
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In triangle PSR:
PQ=PR
So,
∠PRS=PQR
IN ΔPRQ :
∠PRQ+∠RPQ=∠PQS(∴ΔPSQ will become an obtuse angled triangle with ∠PSQ as the obtuse angle)
So the line PS will be longer than line PQ as
According to the The angles ∠PRQ AND ∠RPQ will be smaller than ∠PQS.
PQ=PR
So,
∠PRS=PQR
IN ΔPRQ :
∠PRQ+∠RPQ=∠PQS(∴ΔPSQ will become an obtuse angled triangle with ∠PSQ as the obtuse angle)
So the line PS will be longer than line PQ as
According to the The angles ∠PRQ AND ∠RPQ will be smaller than ∠PQS.
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