plz solve this.............. I dont want Any irrelevant ans
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hey dear here is your answer hope you will satisfy
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GeniusTrippan:
sorry but here u hv to find velocity
v=u ±at
but in question velocity is not mention here speed is mentioned
ok I found the solution of we also check it in the edited answer
v*
thnq so much
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Answer- Initial velocity(u)= 0 m/s
Acceleration(a)= 1 m/s²
Time(t)= 2 minutes
= 120 secondsFinal velocity(v)= ?
Distance(s)= ?
i) Speed acquired/Final Velocity= v
By using 1st equation of motion,v= u + at
v= 0 + 1×120
v= 120 ms⁻¹
ii) Distance travelled= s
By using 3rd equation of motion, 2as= v²-u²
2×1×s= (120)²-(0)²
s= 14400÷2
s= 7200 m
So, speed acquired= 120 m/s and distance travelled= 7200 m.
Please mark as the BRAINLIEST answer if helpful.
Acceleration(a)= 1 m/s²
Time(t)= 2 minutes
= 120 secondsFinal velocity(v)= ?
Distance(s)= ?
i) Speed acquired/Final Velocity= v
By using 1st equation of motion,v= u + at
v= 0 + 1×120
v= 120 ms⁻¹
ii) Distance travelled= s
By using 3rd equation of motion, 2as= v²-u²
2×1×s= (120)²-(0)²
s= 14400÷2
s= 7200 m
So, speed acquired= 120 m/s and distance travelled= 7200 m.
Please mark as the BRAINLIEST answer if helpful.
Gr8
:)
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