Plz solve this... I will mark as brainlist
Attachments:
Answers
Answered by
1
first get the denominator and y2 and 1 and y4 and 1 and y and 1 then factorise them
i dont know if it helped you but i tried to help you
i dont know if it helped you but i tried to help you
Answered by
2
Given Equation is y - 1/y = 9
On Squaring both sides, we get
= > (y - 1/y)^2 = (9)^2
= > y^2 + 1/y^2 - 2 * y * 1/y = 81
= > y^2 + 1/y^2 - 2 = 81
= > y^2 + 1/y^2 = 81 + 2
= > y^2 + 1/y^2 = 83.
Therefore the value of y^2 + 1/y^2 = 83.
Now,
On squaring both sides, we get
= > (y^2 + 1/y^2)^2 = (83)^2
= > y^4 + 1/y^4 + 2 * y^2 * 1/y^2 = 6889
= > y^4 + 1/y^4 + 2 = 6889
= > y^4 + 1/y^4 = 6889 - 2
= > y^4 + 1/y^4 = 6887
Therefore the value of y^4 + 1/y^4 = 6887
Hope this helps!
On Squaring both sides, we get
= > (y - 1/y)^2 = (9)^2
= > y^2 + 1/y^2 - 2 * y * 1/y = 81
= > y^2 + 1/y^2 - 2 = 81
= > y^2 + 1/y^2 = 81 + 2
= > y^2 + 1/y^2 = 83.
Therefore the value of y^2 + 1/y^2 = 83.
Now,
On squaring both sides, we get
= > (y^2 + 1/y^2)^2 = (83)^2
= > y^4 + 1/y^4 + 2 * y^2 * 1/y^2 = 6889
= > y^4 + 1/y^4 + 2 = 6889
= > y^4 + 1/y^4 = 6889 - 2
= > y^4 + 1/y^4 = 6887
Therefore the value of y^4 + 1/y^4 = 6887
Hope this helps!
Similar questions