plz solve this is an question of AP
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an = 10 - 3n
By substituting n = 1, 2, 3, 4, 5, 6, and so on..
a1 = 10 - 3
a1 = 7
a2 = 10 - 3*2
a2 = 10 - 6
a2 = 4
a3 = 10 - 3*3
a3 = 10 - 9
a3 = 1
a4 = 10 - 3*4
a4 = 10 - 12
a4 = - 2
Therefore,
a1, a2, a3, a4......
7, 4, 1, -2 and so on..
d = a2 - a1
d = 4 - 7
d = -3 it is equal for all.
Therefore, it is a sequence of AP.
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Hope it helps you..
johhny:
thnx
Answered by
0
[End term] ⇝An : 10 - 3n
➡To proove the sequence is in A.P
[motive]=> we need to find its C.D
Substituting values of n = 1,2,.......∞
⇝A1 : 10 - 3(1) = 7
⇝A2 : 10 - 3(2) = 4
⇝A3 : 10 - 3(3) = 1
Clearly,
Common difference of A2 - A1 = - 3
Common difference of A3 - A2 = - 3
So, Yes
⇝The given sequence is in A.P
Thanks!
@Aniketchouhan
➡To proove the sequence is in A.P
[motive]=> we need to find its C.D
Substituting values of n = 1,2,.......∞
⇝A1 : 10 - 3(1) = 7
⇝A2 : 10 - 3(2) = 4
⇝A3 : 10 - 3(3) = 1
Clearly,
Common difference of A2 - A1 = - 3
Common difference of A3 - A2 = - 3
So, Yes
⇝The given sequence is in A.P
Thanks!
@Aniketchouhan
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