Math, asked by johhny, 1 year ago

plz solve this is an question of AP

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Answers

Answered by devil1407
6

an = 10 - 3n

By substituting n = 1, 2, 3, 4, 5, 6, and so on..

a1 = 10 - 3

a1 = 7

a2 = 10 - 3*2

a2 = 10 - 6

a2 = 4

a3 = 10 - 3*3

a3 = 10 - 9

a3 = 1

a4 = 10 - 3*4

a4 = 10 - 12

a4 = - 2


Therefore,

a1, a2, a3, a4......

7, 4, 1, -2 and so on..

d = a2 - a1

d = 4 - 7

d = -3 it is equal for all.

Therefore, it is a sequence of AP.

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Hope it helps you..


johhny: thnx
Answered by Anonymous
0
[End term] ⇝An : 10 - 3n

\underline{STEP \: BY \: STEP \: EXPLANATION:-}

➡To proove the sequence is in A.P

[motive]=> we need to find its C.D

Substituting values of n = 1,2,.......∞

⇝A1 : 10 - 3(1) = 7

⇝A2 : 10 - 3(2) = 4

⇝A3 : 10 - 3(3) = 1

Clearly,

Common difference of A2 - A1 = - 3

Common difference of A3 - A2 = - 3

So, Yes

⇝The given sequence is in A.P

Thanks!
@Aniketchouhan
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