Plz solve this, it's urgent. Find k so that the equation has coincident lines: 2x-3y=7 & (k+1)x+(1-2k)y=(5k-4).
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Condition for infininity soln.
a1/a2=b1/b2=c1/c2
2/k+1=-3/1-2k=7/5k-4
Now, 2-4k=-3k-3
5=k
Now, -15k+12=7-14k
-k=-5
k=5
Now, 10k-8=7k+7
3k=15
k=5
a1/a2=b1/b2=c1/c2
2/k+1=-3/1-2k=7/5k-4
Now, 2-4k=-3k-3
5=k
Now, -15k+12=7-14k
-k=-5
k=5
Now, 10k-8=7k+7
3k=15
k=5
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