Question

Plz solve this problem now.​

Answer 1

$</p><p>\underline{\sf Given:}</p><p>\\ </p><p> \sf \rightarrow \quad x + \dfrac{1}{x} = 4 \\ \\</p><p>$

$</p><p>\underline{\sf ToFind:}</p><p>\\ </p><p> \sf \rightarrow \quad x^{2} + \dfrac{1}{x^{2}} = ? \\ \\</p><p></p><p>$

$</p><p>\underline{\sf Solution:}</p><p>\\ \\</p><p>$

$</p><p>\sf \rightarrow \quad x + \dfrac{1}{x} = 4 \\ \\ \sf \quad square \: both \: sides \\ \\ \sf \rightarrow \quad { \bigg( x + \frac{1}{x} \bigg)}^{2} = {4}^{2} \\ \\ \sf \rightarrow \quad {x}^{2} + \frac{1}{ {x}^{2} } + 2 \cdot \cancel{ x} \cdot \frac{1}{ \cancel{x} } = 16 \\ \\ \sf \rightarrow \quad {x}^{2} + \frac{1}{ {x}^{2} } = 14</p><p>$

Answer 2

Answer:

See this.

Explanation:

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