Question

Plz solve this question

Answer 1

According to the figure :- ΔAPO and ΔOQB

∠AOP=∠BOQ (vertically opposite angles) (say x°)
∠PAO=∠OBQ (90°)
∠APO = 180°-(90°+x°)=90°-x°
∠OQB= 180°-(90°+x°)=90°-x°
∴∠APO=∠OQB
Hence ΔAPO≡ ΔOQB by angle-angle property.

∴ Ratio \frac{AO}{OB}= \frac{OP}{OQ}= \frac{AP}{QB}

$\frac{AO}{OB} = \frac{AP}{QB}$

⇒$\frac{6}{4.5} = \frac{4}{QB}$
$QB = \frac{4*4.5}{6} = 3$