plz solve this question
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d=0
b²-4ac=0
4k²-4*9*-1=0
4k²+36=0
4k²=-36
k²=-9
k=3
b²-4ac=0
4k²-4*9*-1=0
4k²+36=0
4k²=-36
k²=-9
k=3
Chhandam:
hey friend the square root of -9 would be iota i.e imaginary roots
Answered by
0
since 9x²+2kx-1 =0 now since it is asked for real roots then D=0
and b²-4ac =0
(2k)² + 4*9 =0
4k²+36= 0
4k² = -36
k² = -9
therefore k = 3i
where i stands for iota or compex roots or imaginary roots
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