Question

plz solve this question

Answer 1

Let larger tap can fills the tank in = x hrs.

then smaller tap will fill the tank in = (x+3) hrs

Part of the tank filled in an hr by both taps =1/x+1/(x+3) acordingly:-

1/x + 1/(x+3) = 1/2

(x+3+x)/x.(x+3) =1/2

or (2x+3)/(x^2+3x) = 1/2

or x^2+3x = 4x+6

or x^2 - x - 6 = 0

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Answer 2

ANS is in my book Mark it's brainliest