PLZ SOLVE THIS QUESTION..
IT'S FROM THE SYLLABUS OF CLASS 10TH...
PLZ ANSWER ONE MORE QUESTION WHAT TO DO WHEN YOU ARE SAD..??? NO SPAMS PLZZZ...
THANK YOU....
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1)because F1 station is at lessar distance than
F2.
now, draw perpendicular to line passing through F1 & F2. at a.
now, dis. from a to f2 = x km.
so , dis, from a to f1 =10-x km
now , tan45° = p/x
1= p/x
p = x.
tan60 = 10-x /x
√3x = 10-x
√3x-x = 10
x( √3-1) = 10
x = 10/√3-1
now rationalize , x = 10×√3+1/√3-1×√3+1
= 10√3-10/2
= 10(√3-1)/2 = 5(√3-1) km. ans.
now,
now ,
F2.
now, draw perpendicular to line passing through F1 & F2. at a.
now, dis. from a to f2 = x km.
so , dis, from a to f1 =10-x km
now , tan45° = p/x
1= p/x
p = x.
tan60 = 10-x /x
√3x = 10-x
√3x-x = 10
x( √3-1) = 10
x = 10/√3-1
now rationalize , x = 10×√3+1/√3-1×√3+1
= 10√3-10/2
= 10(√3-1)/2 = 5(√3-1) km. ans.
now,
now ,
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