Plz solve this question xxxxxx
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Answered by
1
Answer:
13240
Step-by-step explanation:
Given, Principal = 40000, Rate = 10%, Time n = 18 months = (3/2) years.
∴ A = P(1 + r/100)²ⁿ
= 40000(1 + 10/100)³
= 40000(1 + 1/10)³
= 40000(11/10)³
= 53240.
∴ C.I = A - P
= 53240 - 40000
= 13240.
Therefore, Compound Interest = 13240.
Hope this helps!
Answered by
2
Answer:
Principal=40000
Time= 15months = 1 -1/2 years
Rate=10%
Compounded half yearly
Compound Interest=
P(1 +r/2/100)^2×t -P
=40000×(1+5/100)^3 - 40000
=40000×(21/20 ×21/20 ×21/20 -1)
=40000 × (9261 -8000/ 8000)
=40000 ×1261/8000
=5×1261
=6305 rupees
Principal=40000
Time= 15months = 1 -1/2 years
Rate=10%
Compounded half yearly
Compound Interest=
P(1 +r/2/100)^2×t -P
=40000×(1+5/100)^3 - 40000
=40000×(21/20 ×21/20 ×21/20 -1)
=40000 × (9261 -8000/ 8000)
=40000 ×1261/8000
=5×1261
=6305 rupees
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