Question

plz solve.this questions

Answer 1

1ST STEP: 

Always execution starts from main.

Given int A = 50, B = 20 and execute(B) i.e 20.

That means the value of B is passed to x i.e 20.

TEMP = 20 + 200 = 220;
x+=220;
x = x+220;
   = 20 + 220
   = 240.
if(Y!=200)  ----------- This condition is false.That means it comes out of loop.
cout<<A<<B = 50,240.


2ND STEP:

EXECUTE(A, B) = EXECUTE(50,240) (from step (1)).
That means 50 is passed to X and 240 is passed to Y.

TEMP = 50 + 240 = 290.
X+ = TEMP;
X+ = 290;
X=X+290

   = 50 + 290

   = 340.

if(Y!=200)   ---- This condition is true because y value is 240 not 200.

cout<<TEMP<<X<<Y<<end1 value is 290,340,240.


3RD STEP :

The values are passed to cout<<A<<B<<endl; i.e 340,240.(from step(ii)).


The output of the following program is:

50 240
290 340 240
340 240.


Hope this helps!