Math, asked by purbashag, 9 months ago

plz someone help to do this no.​

Attachments:

Answers

Answered by FIREBIRD
5

Step-by-step explanation:

We Have :-

2x^{2}  + yz - 2xy - zx

To Find :-

factorise \: it

Solution :-

2x^{2}  + yz - 2xy - zx \\  \\  \\ it \: can \: be \: written \: as \\  \\  \\ 2x^{2}   - 2xy + yz - zx  \\  \\  \\ taking \: common \\  \\  \\ 2x(x - y) - z(x - y) \\  \\  \\ (x - y)(2x - z)

Answered by Anonymous
2

\large{\underline{\red{\rm{Given:}}}}

2{x}^{2} + yz - 2xy - zx

\large{\underline{\red{\rm{Solution:}}}}

→ Rearranging the terms -

2{x}^{2} - 2xy - zx + yz

Now , taking out the common terms ,

→ 2x ( x - y ) - z ( x - y )

\therefore FINAL ANS → ( 2x - z ) ( x - y )

_______________________________________

Similar questions