Math, asked by madhur1222, 1 year ago

plz tell me fast.......

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Answered by dheeraj68
0
x-a is the factor =>x=a
x^3-5x^2a+4a^2x+m=0
a^3-5a^3+4a^3+m=0
-5a^3+5a^3+m=0
=>m=0
Answered by Sneha3123
0
Heya mate,
Here is your answer,

Q.7
Ans: p(x) = x³-5x²a+4a²x+m

factor = x-a

x-a = 0
=> x = a

p(a) = (a)³-5(a)²a+4a²(a)+m
= a³-5a³+4a³+m
= 5a³-5a³+m
= m

p(a) = 0 {as x-a is the factor so the remainder should be 0}
m = 0


Q.8
Ans:
 { { {(625)}^{ \frac{ - 1}{2} } }^{ \frac{ - 1}{4} } }^{2}  \\  =  {(625)}^{ \frac{ - 1 \times  - 1 \times 2}{2 \times 4} }  \\  =  {(625)}^{ \frac{2}{8} }  \\  =  {(625)}^{ \frac{1}{4} }  \\  =  {(5)}^{4 \times  \frac{1}{4} }  \\  = 5


I tried to explain it in the simplest method hope this is understandable and

Hope this helps

if you have further doubt or want any help, feel free to ask me. I would like and try to help you.

Thank you

#Sneha
☆brainly benefactor☆

madhur1222: thanks you so much
Sneha3123: no prob dear
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