plz tell me fast.......
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x-a is the factor =>x=a
x^3-5x^2a+4a^2x+m=0
a^3-5a^3+4a^3+m=0
-5a^3+5a^3+m=0
=>m=0
x^3-5x^2a+4a^2x+m=0
a^3-5a^3+4a^3+m=0
-5a^3+5a^3+m=0
=>m=0
Answered by
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Heya mate,
Here is your answer,
Q.7
Ans: p(x) = x³-5x²a+4a²x+m
factor = x-a
x-a = 0
=> x = a
p(a) = (a)³-5(a)²a+4a²(a)+m
= a³-5a³+4a³+m
= 5a³-5a³+m
= m
p(a) = 0 {as x-a is the factor so the remainder should be 0}
m = 0
Q.8
Ans:
I tried to explain it in the simplest method hope this is understandable and
Hope this helps
if you have further doubt or want any help, feel free to ask me. I would like and try to help you.
Thank you
#Sneha
☆brainly benefactor☆
Here is your answer,
Q.7
Ans: p(x) = x³-5x²a+4a²x+m
factor = x-a
x-a = 0
=> x = a
p(a) = (a)³-5(a)²a+4a²(a)+m
= a³-5a³+4a³+m
= 5a³-5a³+m
= m
p(a) = 0 {as x-a is the factor so the remainder should be 0}
m = 0
Q.8
Ans:
I tried to explain it in the simplest method hope this is understandable and
Hope this helps
if you have further doubt or want any help, feel free to ask me. I would like and try to help you.
Thank you
#Sneha
☆brainly benefactor☆
madhur1222:
thanks you so much
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