plz tell the answer its urgent no 12
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The formula for Max Ballistic Height is:
h = (V • sin(θ))² / (2•g)
h =is the maximum height.
V =the magnitude of the initial launch velocity
θ =is the launch angle (angle from the local horizontal plane)
g= is the acceleration due to gravity.
In your example, you state that the ball is thrown vertically (θ = 90 degrees), and the sine of 90 is 1. So the formula simplifies to: h = V² / (2•g)
v=5m/s and g= 9.8
so
v^2/2*g
= 5^2/2*9.8
= 25/19.6
= 1.2 meter
1.2 metre is ur answer
h = (V • sin(θ))² / (2•g)
h =is the maximum height.
V =the magnitude of the initial launch velocity
θ =is the launch angle (angle from the local horizontal plane)
g= is the acceleration due to gravity.
In your example, you state that the ball is thrown vertically (θ = 90 degrees), and the sine of 90 is 1. So the formula simplifies to: h = V² / (2•g)
v=5m/s and g= 9.8
so
v^2/2*g
= 5^2/2*9.8
= 25/19.6
= 1.2 meter
1.2 metre is ur answer
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