Question

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Answer 1

Answer:

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Answer 2

Let the fixed charge be Rs x

and charge for each extra day be Rs y

ATQ

x+4y=27. (1)

x+2y=21. (2)

solving the both equations by elimination method:

equation (1)-(2)

4y-2y=6

2y=6

y=3

put y in eqn. (2) we have

x+2(3)=21

x+6=21

x=21-6

x= 15

hence x=15 , y=3

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