Question

plzx ans.....Thnk u....PROVE THE FOLLOWING-:

Answer 1

(1-cosA)(1+secA)
= 1+secA-cosA-secAxcosA
=1+1/cosA-cosA-1/cosAxcosA
=1/cosA-cosA
=1-cos^2A /cosA
=sin^2A/cosA
=sinA x sinA/ cosA
=tanA x sinA=RHS (PROVED)

PLEASE MARK IT AS BRAINLIEST

Answer 2

Given LHS = (1 - cosA)(1 + secA).

$(1 - cosA)(1 + \frac{1}{cosA} )$

$(1 - cosA)( \frac{1+cosA}{cosA})$

$\frac{(1 - cos^2A)}{cosA}$

$\frac{sin^2A}{cosA}$

$\frac{sinA}{cosA} * sinA$

tanA * sinA.


LHS = RHS.


Hope this helps!