Question

plzz ans it immediately....it's 2 much urgent

Answer 1

Answer:

Option - A

Explanation:

Given ratio is 2s:3t.

It is in the form of x:y, then its duplicate ratio is x^2:y^2.

Now,

= > 2s : 3t = (2s - p)^2 : (3t - p)^2

$= \ \textgreater \ \frac{2s}{3t} = (\frac{2s- p}{3t - p} )^2$

$= \ \textgreater \ \frac{2s}{3t} = \frac{4s^2 + 4sp + p^2}{9t^2 - 6tp + p^2}$

= > 2s(9t^2 - 6tp + p^2) = 3t(4s^2 + 4sp + p^2)

= > 18st^2 - 12stp + 2sp^2 = 12s^2t - 12stp + 3tp^2

= > 18st^2 - 12s^2t = 3tp^2 - 2sp^2

= > 6st(3t - 2s) = p^2(3t - 2s)

= > p^2 = 6st.



Hope this helps!