Question

plzz answe fast with solution ​

Answer 1

$\huge \mathfrak{solution}$

from the formula of heat transfer

$\large \boxed{ q = c_vdt}$

now....dt=T2-T1

given that

T1=294.05 k

T2=300.78 k

therefore dt=(300.78-294.05)k=6.73 k

and

$c_v = 8.93 \: kj \:k{}^{-1}\:mol{}^{ - 1}$

therefore....

$\implies{ q = c_vdt} \\ \implies \: q = 8.93 \times 6.73 = 60.1 \: kj \: mol {}^{ - 1}$

therefrom option (a)60.1 ki.mol^-1