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From Chemical Kinetics based on rate of reaction
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Answer
Given that
k = 2.5 × 10−4 mol−1 L s−1
Order of reaction = 0
Decomposition reaction of NH3
Here NH3 has 2 mol then N2 and H2 has 1 and 3 moles respectively
Use the formula of rate of reaction
Use this formula we get
Another formula of rate, Rate = k[NH3]x
Given that order of reaction x = 0
Plug the values we get
Plug the value of k we get
Rate of production of N2 = k = 2.5 × 10−4 mol L-1 s−1
Rate of production of H2 = 3k = 3 x 2.5 × 10−4 mol L-1 s−1 = 7.5 × 10−4 mol L-1 s−1
Answer
Given that
k = 2.5 × 10−4 mol−1 L s−1
Order of reaction = 0
Decomposition reaction of NH3
Here NH3 has 2 mol then N2 and H2 has 1 and 3 moles respectively
Use the formula of rate of reaction
Use this formula we get
Another formula of rate, Rate = k[NH3]x
Given that order of reaction x = 0
Plug the values we get
Plug the value of k we get
Rate of production of N2 = k = 2.5 × 10−4 mol L-1 s−1
Rate of production of H2 = 3k = 3 x 2.5 × 10−4 mol L-1 s−1 = 7.5 × 10−4 mol L-1 s−1
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