plzz answer this..........
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in the figure
join OC
then OB=OC
ANGLE OBC=ANGLE OCB
(ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL)
ANGLE OCP=90 (TANGENT ANGLE)
ANGLE PCA=110
ANGLE ACB=90 (ANGLE IN SEMI CIRCLE)
ANGLE PCB + ANGLE ACB =110
ANGLE PCB=110-90
ANGLE PCB=20
IN TRIANGLE PCO
ANGLE PCB + ANGLE OCB=90
20 + ANGLE OBC=90
ANGLE CBA=70°
join OC
then OB=OC
ANGLE OBC=ANGLE OCB
(ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL)
ANGLE OCP=90 (TANGENT ANGLE)
ANGLE PCA=110
ANGLE ACB=90 (ANGLE IN SEMI CIRCLE)
ANGLE PCB + ANGLE ACB =110
ANGLE PCB=110-90
ANGLE PCB=20
IN TRIANGLE PCO
ANGLE PCB + ANGLE OCB=90
20 + ANGLE OBC=90
ANGLE CBA=70°
Zaysaa:
thanks a lot
np
but how angle OCB BECOME 90 DEGREE
????
where???
last second line
third*
it is 20+ANGLE OCB=90
ohkk i understood. thank u so much.
no problem
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