if the sum of three non zero prime numbers is 100 one of them exceeds other by 36 find largest number
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Answered by
19
Let three prime numbers are X, X+36 and Y.
According to questions,
X +X +36 +Y = 100.
2X +Y = 64 ------------------------- (1)
All three are prime number so 2X should be a even number. Also, to get sum as 100 (even number) Y should be an even prime number i.e 2.
Putting Y = 2
2X +2 = 64
X = 31
Thus, prime numbers are 31, 67 and 2.
According to questions,
X +X +36 +Y = 100.
2X +Y = 64 ------------------------- (1)
All three are prime number so 2X should be a even number. Also, to get sum as 100 (even number) Y should be an even prime number i.e 2.
Putting Y = 2
2X +2 = 64
X = 31
Thus, prime numbers are 31, 67 and 2.
Answered by
4
Answer:
Step-by-step explanation:
Let three prime numbers are X, X+36 and Y.
According to questions,
X +X +36 +Y = 100.
2X +Y = 64 ------------------------- (1)
All three are prime number so 2X should be a even number. Also, to get sum as 100 (even number) Y should be an even prime number i.e 2.
Putting Y = 2
2X +2 = 64
X = 31
Thus, prime numbers are 31, 67 and 2.
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