Plzz i am stuck at this question plzz help
Attachments:
Answers
Answered by
1
@
Proof
In ∆PQA & ∆PRA
Angle PQA = Angle PRA ( each 90° )
PA = PA Common
Angle PAQ = Angle PAR ( AD is bisector of angle A )
∆PQA ≈ ∆PRA by ASA
PQ = PR by CPCT
@:-)
Proof
In ∆PQA & ∆PRA
Angle PQA = Angle PRA ( each 90° )
PA = PA Common
Angle PAQ = Angle PAR ( AD is bisector of angle A )
∆PQA ≈ ∆PRA by ASA
PQ = PR by CPCT
@:-)
Similar questions