plzz solve (ii) it urgent
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let numerator be x and denominator be y
x-1/y=⅓
3x-3=y => 3x-y=3...(1)
x/y+8 = ¼
4x-y=8....(2)
Subtract (1)(2)
3x-y=3
4x-y=8
-. +. -
-x=-5
x= 5
put in (1) 15-3=y => y=12
therfore fraction is 5/12
pls marks as Brainliest
x-1/y=⅓
3x-3=y => 3x-y=3...(1)
x/y+8 = ¼
4x-y=8....(2)
Subtract (1)(2)
3x-y=3
4x-y=8
-. +. -
-x=-5
x= 5
put in (1) 15-3=y => y=12
therfore fraction is 5/12
pls marks as Brainliest
Answered by
0
Let the numerator of fraction is x and denominator is y.
∴ Fraction = x/y.
A/Q,
When 1 is subtracted from numerator = 1/3.
⇒ ( x - 1 ) / y = 1/3
⇒ 3 ( x - 1 ) = y ---- ( 1 )
Now,
If 8 is added to denominator = 1/4
⇒ x / ( y + 8 ) = 1/4
⇒ 4 x = y + 8
⇒ 4x - 8 = y ------ ( 2 ).
From ( 1 ) and ( 2 ) we get,
⇒ 4x - 8 = 3 ( x - 1 )
⇒ 4x - 8 = 3x - 3
⇒ 4x - 3x = -3 + 8
⇒ x = 5.
By substituting the value of x in ( 2 ),
⇒ 4x - 8 = y
⇒ 4 × 5 - 8 = y
⇒ 20 - 8 = y
∴ y = 12.
Hence fraction = x/y = 5/12.
Verification :
When 1 is subtracted from numerator then it becomes 1/3.
= ( 5 - 1 ) / 12
= 4 / 12
= 1/3.
And,
When 8 is added to denominator then it becomes 1/4.
= 5 / ( 12 + 8 )
= 5 / 20
= 1 / 4.
Verified.
Hence, the fraction is 5/12.
∴ Fraction = x/y.
A/Q,
When 1 is subtracted from numerator = 1/3.
⇒ ( x - 1 ) / y = 1/3
⇒ 3 ( x - 1 ) = y ---- ( 1 )
Now,
If 8 is added to denominator = 1/4
⇒ x / ( y + 8 ) = 1/4
⇒ 4 x = y + 8
⇒ 4x - 8 = y ------ ( 2 ).
From ( 1 ) and ( 2 ) we get,
⇒ 4x - 8 = 3 ( x - 1 )
⇒ 4x - 8 = 3x - 3
⇒ 4x - 3x = -3 + 8
⇒ x = 5.
By substituting the value of x in ( 2 ),
⇒ 4x - 8 = y
⇒ 4 × 5 - 8 = y
⇒ 20 - 8 = y
∴ y = 12.
Hence fraction = x/y = 5/12.
Verification :
When 1 is subtracted from numerator then it becomes 1/3.
= ( 5 - 1 ) / 12
= 4 / 12
= 1/3.
And,
When 8 is added to denominator then it becomes 1/4.
= 5 / ( 12 + 8 )
= 5 / 20
= 1 / 4.
Verified.
Hence, the fraction is 5/12.
Anonymous:
Thanks Chanchal
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