Question

plzz solve this question fast i will mark you as brainlsit

Answer 1

tn = 2n² + 3n - 2

when n = 1

t1 = 2(1)² + 3(1) - 2 = 3

when n = 2

t2= 2(2)² + 3(2) - 2 = 12

when n = 3:

t3 = 2(3)² + 3(3) - 2 = 25

when n = 4

t4 = 2(4)² + 3(4) - 2 = 42

Answer: The first 4 terms are 3, 12, 25 and 42

Answer 2

❤❤Here is your answer ✌ ✌

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$tn = 2a {}^{2} + 3n - 2$
when

n=1

2a^2+3n-2
=2×1^2+3×1-2
=2+3-2
=3

n=2

2a^2+3n-2
=2×2^2+3×2-2
=2×4+6-2
=8+6-2
=12

n=3

2a^2+3n-2
=2×3^2+3×3-2
=2×9+9-2
=18+9-2
=25

n=4

2a^2+3n-2
=2×4^2+3×4-2
=2×16+12-2
=32+12-2
=42

The four term of Ap are 3,12,25,42