Question

Plzz tell me fast tomorrow is my exam...
show that the function y(x)=|x|+|x-1| is not differentiable at x=0 and x=1.

Answer 1

Answer:

if x = 0 then answer is (1) and if x = 1 then answer is (1) .

Step-by-step explanation:

For First

Let, x = 0 in y(x) = |x| + |x-1|

       y(x) = |x| + |x-1|

       because, x = 0

       therefore,

                         y(0) = |0| + |0-1|

                                 =  0  + |-1|

                                 =  0 + 1

                                 =  1

---------------------------------------------------------------------

For Second

Let, x = 1 in y(x) = |x| + |x-1|

       y(x) = |x| + |x-1|

       because, x = 1

       therefore,

                         y(1) = |1| + |1-1|

                                 = 1 + 0

                                 = 1

Answer 2

(✿ ♥‿♥)。･:*:･(✿◕3◕)❤(♥ω♥*)(∿°○°)∿ ︵ ǝʌol。･:*:･(✿◕3◕)❤(♥ω♥*)(∿°○°)∿ ︵ ǝʌol。･:*:･(✿◕3◕)❤(∿°○°)∿ ︵ ǝʌol(✿ ♥‿♥)。･:*:･(✿◕3◕)❤