Question

plzzz ans.....PROVE THE FOLLOWING

Answer 1

Hiii there!!!


Here is your answer,



Hope it helps you,
Thank you. :)

Answer 2

HELLO DEAR,

$\frac{ \tan( \alpha ) + \sin( \alpha ) }{ \tan( \alpha ) - \sin( \alpha ) } \\ \\ = \frac{ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } + \sin( \alpha ) }{ \frac{ \sin( \alpha ) }{ \cos( \alpha ) } - \sin( \alpha ) } \\ \\ = \frac{ \sin \alpha (1 + \cos \alpha ) }{ \sin\alpha (1 - cos \alpha )} \\ \\ = \frac{1 + cos \alpha }{1 - cos \alpha } \\ \\ = \frac{ 1 + \frac{1}{sec \alpha } }{1 - \frac{1}{sec \alpha } } \\ \\ = \frac{ \frac{sec \alpha + 1}{sec \alpha } }{ \frac{sec \alpha - 1}{sec \alpha } } \\ \\ = \frac{ sec \alpha + 1}{sec \alpha - 1}$
I HOPE ITS HELP YOU DEAR,
THANKS