Math, asked by ShashankRaj11, 1 year ago

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Answered by Gautam22121998
3
x²-4x+3
ã+ß=[-(-4)]/1
ã+ß=4
and ã.ß=3/1
ã.ß=3
so the polynomial with zeroes 3ã & 3ß will be
x²-(3ã+3ß)x+(3ã.3ß)
x²-3(ã+ß)x+9(ã.ß)
x²-3(4)x+9(3)
x²-12x+27
is the required polynomial
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