Question

plzzz help me.......​

Answer 1

Given :-

• The side of rhombus = 5 cm
• One of the length of diagonal of rhombus = 8 cm

To Find :-

• The length of the other diagonal

Solution :-

• The relation between the diagonals and sides of a rhombus is given by ,

$\\ \star \: {\boxed{\sf{\purple{ \bigg( \dfrac{d_1}{2} \bigg)^{2} + \bigg( \dfrac{d_2}{2} \bigg)^{2} = {s}^{2} }}}}$

$\\ \\ \sf{where}\begin{cases} & \sf{d_1 \& \: d_2 \: are \: diagonal \: of \: rhombus} \\ \\ & \sf{s \: is \: side \: of \: the \: rhombus}\end{cases}$

Substituting the values we have :-

$\\ : \implies \sf \bigg( \dfrac{8}{2} \bigg)^{2} + { \bigg( \dfrac{d_2}{2} \bigg) }^{2} = {(5)}^{2}$

$\\ : \implies \sf \: {(4)}^{2} + { \bigg( \dfrac{d_2}{2} \bigg)}^{2} = 25$

$\\ : \implies \sf 16 + { \bigg( \dfrac{d_2}{2} \bigg)}^{2} = 25$

$\\ : \implies \sf \: { \bigg( \dfrac{d_2}{2} \bigg)}^{2} = 25 - 16$

$\\ : \implies \sf \: { \bigg( \dfrac{d_2}{2} \bigg)}^{2} = 9$

$\\ : \implies \sf \: \bigg( \dfrac{d_2}{2} \bigg) = \sqrt{9}$

$\\ : \implies \sf \:\dfrac{d_2}{2} = 3$

$\\ : \implies \sf \:d_2 = 3 \times 2$

$\\ : \implies \sf{\underline{\boxed {\mathfrak{\pink{d_2 = 6 \: cm}}}}} \: \bigstar$

Hence ,

The length of the other diagonal of the given rhombus is 6 cm

Answer 2

Answer:

ok

Step-by-step explanation:

follow me

d2 = 2[s^2-(d1/2)^2]^0.5.

Example: Side = 5 cm and d1 = 8 cm.

d2 = 2[5^2-(8/2)^2]^0.5

= 2[10–16]^0,5

= 2*6^0.5

= 2*2.4

= 4.8 cm.