plzzz solve it fast no. 11 in the following image through logarithm
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enormous010:
you give me one day i solve it
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a/b=b/c
So, b²=ac
LHS: (a+b+c) (a-b+c) =((a+c) +b) ((a+c) -b) =(a+c) ²-b²=a²+c²+2ac - b²=a²+c²+2b²-b²=a²+b²+c²(RHS)(PROVED)
So, b²=ac
LHS: (a+b+c) (a-b+c) =((a+c) +b) ((a+c) -b) =(a+c) ²-b²=a²+c²+2ac - b²=a²+c²+2b²-b²=a²+b²+c²(RHS)(PROVED)
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i hope this will useful to u
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tnx master
:)
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