plzzzz answer its urgent
Attachments:
Answers
Answered by
2
The answer is - 2a/(2ax+b)²
Now the process
t= ax² + bx
Differentiate it,
dt/dx =2ax +b
So, dx/dt = velocity (v) =1/(2ax + b)
Again differentiate,
dv/dt =Acceleration (a) = - 2a/(2ax + b) ²
.
Hope this is ur required answer.
Now the process
t= ax² + bx
Differentiate it,
dt/dx =2ax +b
So, dx/dt = velocity (v) =1/(2ax + b)
Again differentiate,
dv/dt =Acceleration (a) = - 2a/(2ax + b) ²
.
Hope this is ur required answer.
rakeshmohata:
welcome
its correct
I know!
thank you
my pleasure dear...
thnx.. for brainliest
u r welcome
Similar questions