Math, asked by yuzi57, 3 months ago

plzzzz solve it..... ​

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Answers

Answered by BrainlyEmpire
64

Answer:-

\left(m^2+9\right)^2

Step-by-step explanation:

m^4+18m^2+81

\gray{\mathrm{Let\:}M=m^2}

=M^2+18M+81

\mathrm{Factorise}\:M^2+18M+81:

\gray{\mathrm{Break\:the\:expression\:into\:groups}}

=\left(M^2+9M\right)+\left(9M+81\right)

\gray{\mathrm{Factor\:out\:}M\mathrm{\:from\:}M^2+9M\mathrm{:\quad }M\left(M+9\right)}

\gray{\mathrm{Factor\:out\:}9\mathrm{\:from\:}9M+81\mathrm{:\quad }9\left(M+9\right)}

=M\left(M+9\right)+9\left(M+9\right)

\gray{\mathrm{Factor\:out\:common\:term\:}u+9}

=\left(M+9\right)\left(M+9\right)

\gray{\mathrm{Substitute\:back}\:M=m^2}

=\left(m^2+9\right)\left(m^2+9\right)

\gray{\mathrm{Simplify}}

=\left(m^2+9\right)^2

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Answered by Anonymous
26

Answer:

Answer:-

\left(m^2+9\right)^2

Step-by-step explanation:

m^4+18m^2+81

\gray{\mathrm{Let\:}M=m^2}

=M^2+18M+81

\mathrm{Factorise}\:M^2+18M+81:

\gray{\mathrm{Break\:the\:expression\:into\:groups}}

=\left(M^2+9M\right)+\left(9M+81\right)

\gray{\mathrm{Factor\:out\:}M\mathrm{\:from\:}M^2+9M\mathrm{:\quad }M\left(M+9\right)}

\gray{\mathrm{Factor\:out\:}9\mathrm{\:from\:}9M+81\mathrm{:\quad }9\left(M+9\right)}

=M\left(M+9\right)+9\left(M+9\right)

\gray{\mathrm{Factor\:out\:common\:term\:}u+9}

=\left(M+9\right)\left(M+9\right)

\gray{\mathrm{Substitute\:back}\:M=m^2}

=\left(m^2+9\right)\left(m^2+9\right)

\gray{\mathrm{Simplify}}

=\left(m^2+9\right)^2

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