Math, asked by sakshi345, 1 year ago

plzzzzzzzzzzzzz solve

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Answered by Anonymous
2
hey mate here is ur ans
see the pic hope it is not wrong and helps you frnd
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Answered by siddhartharao77
3
Given :  \frac{4}{3 \sqrt{3}- 2 \sqrt{2}  } +  \frac{3}{3 \sqrt{3} + 2 \sqrt{2} }

= \ \textgreater \   \frac{4(2 \sqrt{2} + 3 \sqrt{3}) + 3(3 \sqrt{3} - 2 \sqrt{2})  }{(2 \sqrt{2} + 3 \sqrt{3} )(3 \sqrt{3}  - 2 \sqrt{2}) }

= \ \textgreater \   \frac{8 \sqrt{2} + 12 \sqrt{3} + 9 \sqrt{3} - 6 \sqrt{2}   }{(3 \sqrt{3})^2 - (2 \sqrt{2} )^2 }

= \ \textgreater \   \frac{2 \sqrt{2} + 21 \sqrt{3}  }{19}

= \ \textgreater \   \frac{2 * 1.414 + 21 * 1.732}{19}

= > 36.3702/19

= > 2.063


Hope this helps!

siddhartharao77: :-)
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