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z² + 19z - 150 is a quadratic equation. Therefore, we need to factorise it by writing the equation as equal to 0.
z² + 19z - 150 = 0
Type into calculator to get (z - 6)(z + 25) = 0.
z - 6 = 0
z = 6
z + 25 = 0
z = -25
∴ z = 6 and -25
z² + 19z - 150 = 0
Type into calculator to get (z - 6)(z + 25) = 0.
z - 6 = 0
z = 6
z + 25 = 0
z = -25
∴ z = 6 and -25
Answered by
3
Hey !
Concept : Given equation is a Quadratic Equation. It can be simplified using a method called Splitting the middle term. Here the Middle terms split in such a way that the sum of the terms after splitting is equal to the middle term and the product of the terms is equal to the product obtained by multiplying the constant and the coefficient of x².
Illustration : z² + 19z - 150
The middle term can be split as ( + 25 ) and ( - 6 ). After splitting we get,
= z² + 25z - 6z - 150 = 0
= z ( z + 25 ) - 6 ( z + 25 ) = 0
=> ( z - 6 ) ( z + 25 ) = 0
=> z = 6, - 25
Hope my answer helped !
Concept : Given equation is a Quadratic Equation. It can be simplified using a method called Splitting the middle term. Here the Middle terms split in such a way that the sum of the terms after splitting is equal to the middle term and the product of the terms is equal to the product obtained by multiplying the constant and the coefficient of x².
Illustration : z² + 19z - 150
The middle term can be split as ( + 25 ) and ( - 6 ). After splitting we get,
= z² + 25z - 6z - 150 = 0
= z ( z + 25 ) - 6 ( z + 25 ) = 0
=> ( z - 6 ) ( z + 25 ) = 0
=> z = 6, - 25
Hope my answer helped !
ar437:
thanxxxxx
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