Point P is the centre of the circle and AB is a diameter.Find the coordinates of point B if coordinates of point A and P are (2,-3) and (-2,0) respectively.
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P is the centre and AB is the diameter of circle.
e.g., A-------------P------------B
here , AP = PB = radius of circle.
It means, P divides the line segment AB in 1 : 1 ratio.
Using midpoint section formula,
I mean, if two points (x₁,y₁) , (x₂,y2) are given then, midpoint of line joining the given points is {(x₁ + x₂)/2 , (y₁ + y₂)/2}
Let B = (x, y) , A = (2, -3)
so, P ≡ (-2,0) ≡ {(-2 + x)/2, (0 + y//2 }
(-2,0) = {(-2 + x)/2 , y/2 }
-2 = (2 + x)/2
⇒-4 = 2 + x
⇒x = -6
0 = (y - 3)/2
⇒0 = y - 3
⇒y = 3
Therefore the coordinates of point B is (-6,3).
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