polynomial x^2 +( a+1)x-6 is 2 find a
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hey there !
p(x) = x² + [a+1 ] x - 6
here 2 is a zero of p(x) ;
p[2] = 2² + [a + 1 ] × 2 - 6
= 4 + 2a + 2 - 6 = 0
=6 - 6 + 2a = 0
2a = 0
a = 0/2 = 0
p(x) = x² + [a+1 ] x - 6
here 2 is a zero of p(x) ;
p[2] = 2² + [a + 1 ] × 2 - 6
= 4 + 2a + 2 - 6 = 0
=6 - 6 + 2a = 0
2a = 0
a = 0/2 = 0
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