Question

position (X) VERSUS TIME (T) graph of a particle moving in a straight line is shown in the figure .the velocity ratio of a particle at 1.5 seconds and 2.5 seconds

Answer 1

Tanu here Slope= velocity

dx/dt =h/1.....for 1.5sec

And h/2 for 2.5 sec

Ratio 2/1

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Answer 2

We know that, $velocity = distance/ time$

                                Velocity= slope of the distance vs time graph

Velocity at 1.5s = slope of the lower part of the graph

                         = (-h/1) (if graph creates acute angle , slope is negative)

                         = -h

Velocity at 2.5s = slope of the lower part of the graph

                          = h/2(if graph creates obtuse angle , slope is positive)

Velocity ratio of the particle = Velocity at 1.5s/ Velocity at 2.5s

                                               =(-1/h)/(2/h)

Velocity ratio of the particle = -1/2