Question

PQ and PT are tangents drawn from a point p to a circle with centre o such that angle QPT=120 then angle QOT is equal to​

Answer 1

Answer:

Given ∠QPR=120

0

Radius is perpendicular to the tangent at the point of contact.

∴∠OQP=90

0

⇒∠QPO=60

0

(tangent drawn to a circle from an external point are equally inclined to the segment, joining the center to that point).

In ΔQPO,cos60

0

=

PO

PQ

⇒

2

1

=

PO

PQ

⇒2PQ=PO