PQ is a chord of a circle and PT is the tangent at P such that ‘O’ is the centre of the circle then is equal to_______
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Answer: OPR=90( radius is always perpendicular to tangent)
RPQ+QPO=90
QPO=90-50
QPO=40
OP=OQ (radii)
OPQ=OQP=40(angles opp to equal sides)
In triangle OPQ
OPQ+OQP+POQ=180(ASP)
POQ=180-80
POQ=100
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Answer:
Answer: OPR=90( radius is always perpendicular to tangent)
RPQ+QPO=90
QPO=90-50
QPO=40
OP=OQ (radii)
OPQ=OQP=40(angles opp to equal sides)
In triangle OPQ
OPQ+OQP+POQ=180(ASP)
POQ=180-80
POQ=100
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