PQR IS a triangle in which pq=pr .s is a point on the side pq.through s,a line is drawn parallel to qr intersecting pr at t.prove ps=pt
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inΔ PQR ,
PQ =PR
⇒∠PRQ = ∠PQR ------(1)
∠PQR = ∠PST ---------(2)
∠PRQ = ∠PTS ---------(3)
BUT ∠PQR = ∠PRQ , FRM (1) AND (2) WE GET ∠PST = ∠PTS
IN ΔPST ,WE HAVE
∠PST = ∠PTS
⇒PT = PS
PQ =PR
⇒∠PRQ = ∠PQR ------(1)
∠PQR = ∠PST ---------(2)
∠PRQ = ∠PTS ---------(3)
BUT ∠PQR = ∠PRQ , FRM (1) AND (2) WE GET ∠PST = ∠PTS
IN ΔPST ,WE HAVE
∠PST = ∠PTS
⇒PT = PS
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