Question

PQR is a triangle in which PQ=QR=26 S is the point on QR such that SR=3cm and PS=25cm find QS

Answer 1

Step-by-step explanation:

By apollonius theorem

PQ^2+PR^2=2PS^2+2QS^2

26^2+26^2=2(PS^2+QS^2)

2(26^2)=2(PS^2+QS^2)

26^2=25^2+QS^2

QS^2+625=676

QS^2=676-625

QS^2=51

QS=root51 cm.