Question

PQR is an equilateral triangle with coordinates Q(0,6) , R(0,-6) . Find the coordinates of the vertex P. pls answer....i will mark as brainleist and pls no spam answers thank you

Answer 1

Answer:

From the attached figure, the distance between Q and R is 4 + 4 =8

Hence, QR = 8

Since, it is an equilateral triangle. Hence, all the sides are equal.

Therefore, PQ = PR = QR = 8

Now, vertex p is on the x axis. Hence, the y coordinate is 0.

Let the vertex p is (x,0)

Thus, we have

PQ = 8

\begin{lgathered}\sqrt{0-4)^2+(x-0)^2}=8\\\\16+x^2=8^2\\x^2=64-16\\x^2=48\\x=\sqrt{48}\\x=6.93\end{lgathered}0−4)2+(x−0)2=816+x2=82x2=64−16x2=48x=48x=6.93