∆PQR is right angled at Q. A and B are the mid-points of sides PQ and PR respectively. If PQ=10 cm and PR=26 cm, then find the length of AB
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OK so by using the mid point theorem...AB=1/2QR and also AB||QR..so Angle PAB=90°(alternate angles)..so in Triangle PAB..PA=10/2=5cm and PB=26/2=13cm..so by using Pythagoras theorem=>AB^2=PB^2-PA^2=169-25=144=AB^2... so AB=12cm(ans)
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Given,
∆ PQR is right-angled at Q.
A and B are the mid-points of sides PQ and PR respectively.
PQ=10 cm and PR=26 cm
To find,
The length of AB.
Solution,
The length of AB will be 12 cm.
We can easily solve this problem by following the given steps.
According to the question,
∆ PQR is right-angled at Q.
A and B are the mid-points of sides PQ and PR respectively.
PQ=10 cm and PR=26 cm
AP = 10/2 cm = 5 cm
AP = 10/2 cm = 5 cmPB = 26/2 cm = 13 cm --- (mid-points)
When ∆ PQR is right-angled at Q then ∆ PAB will also be right-angled at A.
Using Pythagoras theorem in ∆PAB,
PB² = AP²+AB²
AB² = PB²-AP²
AB² = (13)²-(5)²
AB² = 169-25
AB² = 144
AB = √144
AB = 12 cm
Hence, the length of AB is 12 cm.
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