PQRS is a parallelogram .Xand Y are midpoints of sides PQ and RS respectively. If W and Z are points on intersection of SX&PY and XR& YQ respectively, then show that ar(∆YWZ)=ar(∆XWZ)
Attachments:
Answers
Answered by
4
PQRS is a llgm
and X & Y are midpoint of sides PQ AND RS respectively.
in quad. XQYS,
SY = QX AND ALSO SY ll QX
therefore quad XQYS is a llgm.
In quad.PXRY ,
PX = YR & PX ll YR.
therefore quad PXRY is a llgm.
also in quadrilateral XZYW
XW ll YZ
YW ll ZX
therefore XZYW is a llgm.
therefore ar(YWZ) = ar(XWZ).
as WZ is the diagonal of the parellelogram
& we know that the diagonal of a llgm divides it into two triangles of equal areas.
and X & Y are midpoint of sides PQ AND RS respectively.
in quad. XQYS,
SY = QX AND ALSO SY ll QX
therefore quad XQYS is a llgm.
In quad.PXRY ,
PX = YR & PX ll YR.
therefore quad PXRY is a llgm.
also in quadrilateral XZYW
XW ll YZ
YW ll ZX
therefore XZYW is a llgm.
therefore ar(YWZ) = ar(XWZ).
as WZ is the diagonal of the parellelogram
& we know that the diagonal of a llgm divides it into two triangles of equal areas.
Answered by
0
Answer:
3 pens and 5 pencils cost
14 rupees. . what will be the cost of 12 pens and 20 pencils
(a) rupees 42. (b) rupees 56
(c) rupees 70. (d) rupees 112
Similar questions