Math, asked by atulchoudhary33, 11 months ago

. PQRS is a rhombus . If PO = 4 cm and OQ = 3 cm then what is PR +
SQ?​

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Answers

Answered by V29517
21

Step-by-step explanation:

Since diagonals of a rhombus bisect each other at right angles,

PO = OR and OQ = OS

PO+OR = PR

(4+4) = PR

PR = 8 cm

OQ+OS = SQ

(3+3) = SQ

SQ = 6 cm

Answered by samudra67
8

since diagonals of a rhombus bisect at right angles

so PO=OR AND SO=QO

Now PO=4cm

so,OR=4cm

therefore PR=4+4=8cm

and OQ=3cm

so,SO=3cm

therefore SQ=3+3=6cm

now PR+SQ=8+6=14cm

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