↔PR || ↔XY and ↔CD is the transversal, if ∠PGC = 65°, find the measure of the remaining angles.
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SOLUTION:-
GIVEN BY:-
PR || XY and CD is transversal.
∠PGC = 65°
then,
∠CGR = 180 - 65 = 115
∠CGR = ∠PGK = 115
∠PGK = ∠XKD = 115
∠XKD = ∠GKY = 115
and
∠PGC = ∠RGK = 65
∠RGK = ∠YKD = 65
∠YKD = ∠GKD = 65
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GIVEN BY:-
PR || XY and CD is transversal.
∠PGC = 65°
then,
∠CGR = 180 - 65 = 115
∠CGR = ∠PGK = 115
∠PGK = ∠XKD = 115
∠XKD = ∠GKY = 115
and
∠PGC = ∠RGK = 65
∠RGK = ∠YKD = 65
∠YKD = ∠GKD = 65
■I HOPE ITS HELP■
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It is given that ,
PR // XY , CD is the transversal ,
<1 = 65° ( given )
i ) <1 = <3 = 65°
[ vertically opposite angles]
ii ) <1 + <2 = 180° [ linear pair ]
65° + <2 = 180
=> <2 = 180 - 65
=> <2 = 115°
iii ) <2 = <4 = 115 °
[ vertically opposite angles ]
iv ) <1 = <5 [ corresponding angles ]
v ) <5 = <7
[ vertically opposite angles ]
vi ) <2 = <6
[ corresponding angles ]
vii ) <6 = <7
[ vertically opposite angles ]
Therefore ,
<1 = <3 = <5 = <7 = 65°
<2 = <4 = <6 = <8 = 115°
••••
PR // XY , CD is the transversal ,
<1 = 65° ( given )
i ) <1 = <3 = 65°
[ vertically opposite angles]
ii ) <1 + <2 = 180° [ linear pair ]
65° + <2 = 180
=> <2 = 180 - 65
=> <2 = 115°
iii ) <2 = <4 = 115 °
[ vertically opposite angles ]
iv ) <1 = <5 [ corresponding angles ]
v ) <5 = <7
[ vertically opposite angles ]
vi ) <2 = <6
[ corresponding angles ]
vii ) <6 = <7
[ vertically opposite angles ]
Therefore ,
<1 = <3 = <5 = <7 = 65°
<2 = <4 = <6 = <8 = 115°
••••
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