Question

practice application of refraction of light any 3 and explain ​

Answer 1

Explanation:

Refraction of Light Rays at Interfaces

Light rays travel in different mediums at different speeds. In vacuum, for example, light travels at the speed of 3×108 m/s. This is the highest speed possible in physics.

One of the most important parameters that measures optical properties of a medium is the index of refraction. It is defined as the ratio of the speed of light in vacuum (3×108 m/s) and the speed of light v in the medium in question.

The refractive index measure the optical density of a given material. A material with higher refractive is more optically dense than a material with lower refractive index.

n =

c

v

Example 1

What is the index of refraction in a medium where the speed of light is 1.5×108 m/s?

Solution

n =

c

v

=

3×108 m/s

1.5×108 m/s

= 2